Plant Physiology — Photosynthesis, Respiration & Transport (Class 11)

Light and dark reactions of photosynthesis, C3 and C4 plants, cellular respiration, Krebs cycle, transport in plants, transpiration. NCERT Class 11.

CBSE NEET 17 min read

What Plant Physiology Is Really About

Plants pull off something no animal can — they make their own food using sunlight, water, and CO₂. But that’s just the start. They also break down that food for energy, move water from roots to the topmost leaf, and lose water through tiny pores. Understanding these processes is not optional for NEET — roughly 8-10 marks come from this chapter every year.

The key insight: photosynthesis and respiration are not opposite processes that cancel each other out. They’re complementary cycles linked by common molecules (ATP, NADPH, glucose). Once you see the molecular logic, the reaction sequences stop feeling like rote memorisation and start feeling inevitable.

Let’s work through each process carefully, then connect them.


Key Terms & Definitions

Photosynthesis — The process by which chlorophyll-containing organisms convert light energy into chemical energy stored as glucose. Overall equation: 6CO2+6H2OlightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{light} C_6H_{12}O_6 + 6O_2

Light Reactions (Hill Reactions) — The light-dependent steps of photosynthesis occurring in the thylakoid membranes. Produce ATP, NADPH, and O₂. Named after Robin Hill.

Calvin Cycle (Dark Reactions / C3 cycle) — Light-independent reactions in the stroma. Use ATP and NADPH to fix CO₂ into glucose. The “dark” label is misleading — they run in light too, just don’t directly need it.

RuBisCO — Ribulose-1,5-bisphosphate carboxylase/oxygenase. The most abundant enzyme on Earth. Catalyses CO₂ fixation in C3 plants.

Photorespiration — RuBisCO fixing O₂ instead of CO₂, wasting energy. Significant in C3 plants, minimal in C4 plants.

Kranz Anatomy — The characteristic two-cell arrangement (mesophyll + bundle sheath cells) in C4 plants. Allows CO₂ concentration around RuBisCO.

Glycolysis — Breakdown of glucose to 2 pyruvate in the cytoplasm. Occurs in both aerobic and anaerobic respiration.

Krebs Cycle (TCA Cycle) — Occurs in mitochondrial matrix. Completely oxidises pyruvate, generating NADH, FADH₂, and CO₂.

Oxidative Phosphorylation — ATP synthesis using the electron transport chain (ETC) in the inner mitochondrial membrane. The main ATP factory.

Transpiration — Loss of water vapour from aerial parts of plants, mainly through stomata. Creates the transpiration pull that drives water movement.

Apoplast / Symplast — Two pathways for water movement across root cortex. Apoplast: through cell walls (faster). Symplast: through cytoplasm via plasmodesmata.


Photosynthesis — The Detailed Mechanism

Light Reactions: Where Energy Gets Captured

The thylakoid membrane contains two photosystems working in tandem.

Photosystem II (PS II) absorbs at 680 nm. Light excites chlorophyll, ejecting high-energy electrons. Water splits (photolysis) to replace these electrons: 2H2O4H++4e+O22H_2O \rightarrow 4H^+ + 4e^- + O_2. This is where all the O₂ we breathe comes from.

Photosystem I (PS I) absorbs at 700 nm. Re-energises the electrons from PS II. These electrons ultimately reduce NADP⁺ to NADPH.

The sequence is PS II → electron transport chain → PS I → NADPH. Many students write it backwards in exams. Remember: light hits PS II first (even though the numbers suggest otherwise). The numbering reflects order of discovery, not function.

Cyclic Photophosphorylation — Only PS I is used. Electrons cycle back to PS I through the ETC. Produces only ATP (no NADPH, no O₂). This supplements ATP when the cell needs more ATP relative to NADPH.

Non-cyclic Photophosphorylation — Both PS II and PS I used. Produces ATP + NADPH + O₂. This is the main route.

18 ATP+12 NADPH+6 O218 \text{ ATP} + 12 \text{ NADPH} + 6 \text{ O}_2

These numbers matter for NEET numericals. For every molecule of glucose synthesised, the Calvin cycle runs 6 times total, requiring 18 ATP and 12 NADPH.

Calvin Cycle: Where Glucose Gets Built

Three phases — carboxylation, reduction, regeneration.

Carboxylation — CO₂ combines with RuBP (5-carbon) via RuBisCO to form an unstable 6-carbon intermediate that immediately splits into two molecules of 3-phosphoglycerate (3-PGA) — a 3-carbon compound. This is why C3 plants are called C3.

Reduction — 3-PGA is reduced to G3P (glyceraldehyde-3-phosphate) using ATP and NADPH. G3P is the actual carbohydrate output of the cycle.

Regeneration — Most G3P molecules regenerate RuBP (using more ATP) so the cycle continues. Only 1 out of every 6 G3P leaves to form glucose.

NEET frequently asks: “How many turns of the Calvin cycle are needed to produce one glucose molecule?” Answer: 6 turns (fixing 6 CO₂). Also know that the cycle was elucidated by Melvin Calvin using radioactive 14C^{14}C — a 2-mark question that appeared in NEET 2019.

C4 Plants: Solving the Photorespiration Problem

C3 plants waste energy when RuBisCO fixes O₂ instead of CO₂ — this is photorespiration. C4 plants (maize, sugarcane, sorghum) evolved a workaround using Kranz anatomy.

In mesophyll cells, CO₂ is first fixed by PEP carboxylase (which has zero affinity for O₂) to form oxaloacetate (OAA, 4-carbon) — hence “C4”. OAA converts to malate, which is pumped into bundle sheath cells.

In bundle sheath cells, malate releases CO₂. Now RuBisCO operates in a CO₂-rich, O₂-poor environment. No photorespiration. More efficient.

CAM plants (cacti, pineapple) do temporal separation instead of spatial — fix CO₂ at night, run Calvin cycle during the day, keeping stomata closed to prevent water loss.


Cellular Respiration — Breaking Glucose Down

Glycolysis (Cytoplasm)

Glucose (6C) → 2 Pyruvate (3C) + 2 ATP (net) + 2 NADH

The 2 ATP is net — glycolysis consumes 2 ATP to start, produces 4, so net = 2.

This step doesn’t need oxygen. It’s the only energy-generating step available in anaerobic conditions.

Pyruvate Oxidation (Mitochondrial Matrix)

Each pyruvate → Acetyl CoA (2C) + CO₂ + NADH

The CO₂ from this step is what you exhale when you exhale CO₂. Catalysed by the pyruvate dehydrogenase complex.

Krebs Cycle / TCA Cycle (Mitochondrial Matrix)

Per turn (1 acetyl CoA):

  • 2 CO₂ released
  • 3 NADH produced
  • 1 FADH₂ produced
  • 1 GTP produced (≈ 1 ATP)

Since each glucose gives 2 acetyl CoA, 2 turns per glucose.

6 NADH+2 FADH2+2 GTP+8 CO2 (from 2 turns)6 \text{ NADH} + 2 \text{ FADH}_2 + 2 \text{ GTP} + 8 \text{ CO}_2 \text{ (from 2 turns)}

Oxidative Phosphorylation (Inner Mitochondrial Membrane)

NADH and FADH₂ donate electrons to the ETC. Electrons pass through Complex I → III → IV. Protons are pumped across the membrane, creating a gradient. ATP synthase (Complex V) uses this gradient to make ATP — this is chemiosmosis, proposed by Peter Mitchell.

  • 1 NADH → ~2.5 ATP
  • 1 FADH₂ → ~1.5 ATP

Total ATP per glucose (theoretical): ~36-38 ATP. NEET 2022 specifically asked about the “biological significance” of anaerobic respiration — know that it regenerates NAD⁺ to keep glycolysis running when O₂ is absent.

Fermentation

When O₂ is absent, pyruvate takes alternate routes:

  • Yeast: Pyruvate → Ethanol + CO₂ (using alcohol dehydrogenase). Used in baking (CO₂ raises bread) and brewing.
  • Muscle cells: Pyruvate → Lactate. Causes the burning sensation during intense exercise.

Transport in Plants

Water Movement: From Soil to Leaf

Water enters root hair cells by osmosis (higher water potential in soil than in root cells). It then moves inward via:

  • Apoplast pathway — through cell walls. Fast, but blocked at the Casparian strip in endodermis.
  • Symplast pathway — through cytoplasm via plasmodesmata.

At the endodermis, all water must switch to the symplast (Casparian strip blocks apoplast). This allows selective ion uptake.

Water then enters xylem. The driving force for upward movement is transpiration pull (cohesion-tension theory by Dixon and Joly). Water has high cohesion (water-water attraction) and adhesion (water-xylem wall attraction), allowing a continuous water column under tension.

Root pressure is the other force — it can push water up to ~10m. Transpiration pull handles the rest (some trees are 100m tall). NEET often asks which force is dominant — answer is transpiration pull.

Transpiration and Stomatal Regulation

Stomata open when guard cells become turgid. Guard cells have unevenly thickened walls — the inner wall is thicker. When turgor increases, the thinner outer wall expands more, bowing outward and opening the pore.

What causes guard cells to become turgid?

  • Light → K⁺ uptake by guard cells → water follows by osmosis → turgor increases
  • CO₂ depletion (from photosynthesis) also triggers opening

Significance of transpiration:

  1. Creates the pull for water movement (cohesion-tension)
  2. Cools the leaf (evaporative cooling)
  3. Concentrates minerals in leaves

Phloem Transport: Sugar Movement

Sucrose moves from source (leaves) to sink (roots, fruits, growing tips) via phloem — this is translocation.

The pressure flow hypothesis (Münch): sucrose is actively loaded into phloem at source → osmotic water entry → high pressure. At sink, sucrose unloaded → pressure drops. This pressure difference drives bulk flow.

NEET loves the distinction: xylem transport is passive (physical forces), phloem transport is active (requires ATP for sucrose loading). This has appeared as a direct question in NEET 2021 and 2023.


Solved Examples

Example 1 — CBSE Level

Q: During a Calvin cycle, how many ATP and NADPH molecules are consumed to fix 3 molecules of CO₂?

3 CO₂ → 3 turns of Calvin cycle.

Per turn: 3 ATP consumed in carboxylation + reduction, 2 NADPH consumed in reduction.

Wait — let’s be precise. To fix 1 CO₂: 3 ATP and 2 NADPH are used (this is a standard result).

For 3 CO₂: 9 ATP and 6 NADPH.

The output is 1 molecule of G3P (not glucose — for glucose you need 6 CO₂ and 6 turns).

Example 2 — NEET Level

Q: In a C4 plant, CO₂ is first fixed in mesophyll cells to form a 4-carbon compound. This compound is then transported to bundle sheath cells where CO₂ is released. What is the advantage of this arrangement?

The advantage is the elimination of photorespiration.

In bundle sheath cells, CO₂ is released from malate, creating a high CO₂ / low O₂ environment. RuBisCO (which is only present in bundle sheath cells in C4 plants) operates exclusively as a carboxylase, not an oxygenase. No photorespiration → no energy waste → higher photosynthetic efficiency. This is why C4 crops like maize outperform C3 crops like wheat in hot, sunny conditions.

Example 3 — NEET / Advanced Level

Q: A student claims that anaerobic respiration is completely wasteful compared to aerobic respiration. Is this accurate?

Not accurate. Anaerobic respiration serves a critical function: NAD⁺ regeneration.

Glycolysis produces NADH. If NADH accumulates, NAD⁺ runs out and glycolysis stops — no ATP at all. Fermentation oxidises NADH back to NAD⁺, keeping glycolysis running.

In cells with sudden high energy demand (e.g., muscle during sprinting), oxygen delivery is insufficient. Lactic acid fermentation allows continued ATP production, albeit at low efficiency (2 ATP vs. 36-38 in aerobic). Without it, the muscle cell would get zero ATP from glycolysis.


Exam-Specific Tips

NEET Weightage: Plant physiology (photosynthesis + respiration + transport) contributes approximately 8-12 marks per year. High-yield subtopics: C3 vs C4 comparison, ETC and ATP yield, phloem loading/unloading, cohesion-tension theory.

CBSE Board: Expect 5-mark questions requiring the complete pathway of either the Calvin cycle or Krebs cycle with all intermediates. Diagrams of Z-scheme (non-cyclic photophosphorylation) are frequently asked in Class 11 practicals.

NEET PYQ Pattern: 2024 asked about the specific location of the light reactions (thylakoid) vs dark reactions (stroma). 2023 had a question on the role of Casparian strip. Know these locations precisely.


Common Mistakes to Avoid

Mistake 1: Confusing PS I and PS II sequence. PS II acts first — it absorbs at P680 and splits water. PS I absorbs at P700 and produces NADPH. The numbering is by discovery order, not functional order. Write the sequence as: PS II → ETC → PS I.

Mistake 2: Saying “dark reactions don’t need light.” The Calvin cycle doesn’t directly require light, but it stops quickly in darkness because ATP and NADPH (produced in light reactions) run out. In NEET MCQs, the correct phrasing is “light-independent” — not “don’t require light.”

Mistake 3: Incorrect ATP count from glycolysis. Gross ATP production = 4. But 2 ATP are invested at the start. Net = 2 ATP. Writing “4 ATP” in an exam costs you marks.

Mistake 4: Thinking xylem transport needs energy. Xylem transport is passive — driven by transpiration pull and root pressure. Only phloem loading/unloading requires ATP. This distinction is a favourite trap question.

Mistake 5: Mixing up CO₂ fixation sites in C4 plants. CO₂ is fixed first in mesophyll cells (by PEP carboxylase). Calvin cycle runs in bundle sheath cells. RuBisCO is present only in bundle sheath cells in C4 plants. Students often write it the other way around.


Practice Questions

Q1. What is the primary electron donor in the light reactions of photosynthesis?

Water (H2OH_2O). During photolysis at PS II, water is split: 2H2O4H++4e+O22H_2O \rightarrow 4H^+ + 4e^- + O_2. The electrons replace those lost by excited chlorophyll in PS II.


Q2. Name the enzyme responsible for CO₂ fixation in C3 plants and the first stable product of this fixation.

Enzyme: RuBisCO (ribulose-1,5-bisphosphate carboxylase/oxygenase). First stable product: 3-phosphoglycerate (3-PGA), a 3-carbon compound. This is why plants using this pathway are called C3 plants.


Q3. A yeast cell is placed in anaerobic conditions with glucose. What products accumulate and why?

Ethanol and CO₂ accumulate. Pyruvate (from glycolysis) is converted to acetaldehyde by pyruvate decarboxylase, then to ethanol by alcohol dehydrogenase. This process regenerates NAD⁺, allowing glycolysis to continue producing ATP.


Q4. What would happen to transpiration if all stomata of a plant were artificially sealed?

Transpiration would decrease by ~90% (most water loss occurs through stomata). Cuticular transpiration (through waxy cuticle) would continue at a very low rate. Consequently, the transpiration pull would be lost, and water would not rise to the upper leaves — the plant would wilt even if soil water is available.


Q5. In the Krebs cycle, at which steps is CO₂ released? How many CO₂ molecules are released per turn?

CO₂ is released at two decarboxylation steps:

  1. Isocitrate → α-ketoglutarate (1 CO₂)
  2. α-ketoglutarate → succinyl CoA (1 CO₂)

So 2 CO₂ per turn. Since glucose produces 2 acetyl CoA, the Krebs cycle releases 4 CO₂ per glucose from these steps. The other 2 CO₂ per glucose are released during pyruvate oxidation (pyruvate → acetyl CoA).


Q6. How does the Casparian strip help in selective mineral absorption?

The Casparian strip is a band of suberin (waxy material) in the radial and transverse walls of endodermal cells. It blocks the apoplast pathway — water and solutes cannot bypass the endodermal cells via cell walls.

All materials must pass through the plasma membrane of endodermal cells (symplast). The cell membrane acts as a selective barrier, allowing only required ions to enter and excluding harmful ones. This is why plants don’t absorb all soil minerals indiscriminately.


Q7. Differentiate between cyclic and non-cyclic photophosphorylation in terms of products and photosystems involved.

FeatureCyclicNon-Cyclic
PhotosystemsPS I onlyPS I + PS II
ProductsATP onlyATP + NADPH + O₂
Electron donorNone (electrons cycle)Water
O₂ evolutionNoYes

Cyclic photophosphorylation supplements ATP when NADPH supply exceeds demand (e.g., when CO₂ fixation is slow).


Q8. A plant is placed in a solution with a solute potential of −8 bars. The plant cells have a water potential of −12 bars. In which direction will water move?

Water moves from higher water potential to lower water potential.

Solution water potential = −8 bars. Plant cell water potential = −12 bars.

Since −8 > −12, water moves from the solution into the plant cells. The plant will absorb water (it will become more turgid).


Q9. Why are C4 plants more efficient than C3 plants in hot, dry conditions?

Three reasons work together:

  1. No photorespiration — PEP carboxylase in mesophyll cells has no affinity for O₂. CO₂ is concentrated around RuBisCO in bundle sheath cells, preventing O₂ from binding.

  2. Better water use efficiency — C4 plants can fix CO₂ with stomata only partially open, losing less water per unit of carbon fixed.

  3. Temperature optimum — RuBisCO’s affinity for CO₂ decreases at high temperatures, making photorespiration worse in C3 plants. C4 plants circumvent this by keeping CO₂ concentration high regardless of temperature.


FAQs

Why does photosynthesis release oxygen if plants also need oxygen for respiration?

Plants do need oxygen for aerobic respiration, but during daytime, the rate of photosynthesis is 20-30 times faster than respiration. The oxygen produced vastly exceeds what the plant consumes. At night, only respiration runs, so plants consume O₂. The net effect over 24 hours is O₂ release — which is why plants are net oxygen producers.


What is the Z-scheme in photosynthesis?

The Z-scheme describes the path of electrons during non-cyclic photophosphorylation. When drawn as a graph of energy levels vs. time, the electron path traces a Z-shape: high energy at PS II → drops through ETC → boosted again at PS I → high energy NADPH. The name has nothing to do with the letter Z having any inherent significance — it’s purely a visual description of the energy diagram.


Is glycolysis the same in aerobic and anaerobic respiration?

Yes — glycolysis is identical in both. The difference begins with pyruvate’s fate. In aerobic conditions, pyruvate enters mitochondria for the Krebs cycle. In anaerobic conditions, pyruvate is reduced in the cytoplasm (to lactate or ethanol) to regenerate NAD⁺. Glycolysis itself is always the same 10-step sequence producing 2 ATP and 2 NADH per glucose.


What happens if RuBisCO oxygenase activity increases?

This is photorespiration. When O₂ concentration is high relative to CO₂ (as in hot, sunny conditions), RuBisCO adds O₂ to RuBP instead of CO₂. This produces phosphoglycolate (2C) instead of 3-PGA. The cell must spend ATP to recycle phosphoglycolate — energy is wasted, CO₂ is released, and net photosynthesis drops. C4 and CAM plants evolved precisely to minimise this.


Why is the inner mitochondrial membrane important for ATP synthesis?

The inner membrane is impermeable to protons (H⁺). The ETC pumps protons from the matrix to the intermembrane space, creating a proton gradient. The only way for protons to return to the matrix is through ATP synthase (Complex V). This forces proton flow through ATP synthase, driving ATP synthesis — chemiosmosis. If the membrane were freely permeable to protons, the gradient would dissipate and no ATP would be made (this is how certain uncoupling agents work as poisons).


How do plants transport sugars upward and downward simultaneously?

Phloem transport is bidirectional — different sieve tubes move sucrose in different directions simultaneously. A leaf (source) exports sucrose downward to roots (sink) through some phloem elements. A fruit (strong sink) pulls sucrose upward from lower leaves through other phloem elements. Each sieve tube moves material in one direction at a time, but different tubes can move in opposite directions. This is why phloem translocation is described as bidirectional overall but unidirectional within any single sieve tube.


What is the difference between water potential and osmotic potential?

Water potential (Ψ) is the total free energy of water in a system, determining the direction of water movement. It’s the sum of osmotic potential and pressure potential: Ψ=Ψs+Ψp\Psi = \Psi_s + \Psi_p

Osmotic potential (Ψs, also called solute potential) is always negative — it reflects the reduction in water potential due to dissolved solutes. More solutes = more negative osmotic potential.

Pressure potential (Ψp) is usually positive in turgid plant cells (the wall pushes back on the water). In xylem, it’s negative (tension from transpiration pull).

Pure water has Ψ=0\Psi = 0. Water always moves from less negative to more negative water potential — from Ψ=5\Psi = -5 bars to Ψ=12\Psi = -12 bars, for example.

Practice Questions