Digestion And Absorption: Numerical Problems Solved Step-by-Step

medium CBSE NEET 3 min read

Digestion And Absorption: Numerical Problems Solved Step-by-Step

When we work on Digestion And Absorption, numerical problems trip up even strong students — not because the biology is hard, but because the arithmetic setup gets messy. Let’s solve a few together the way a tutor would at the board.

Question 1 — Setting Up Ratios

A population study on digestion and absorption gives us 240 observed units in one sample and 180 in another. If the expected ratio is 4:3, are the samples matching expectation?

Total observed =240+180=420= 240 + 180 = 420. Expected in 4:3 split =47×420=240= \frac{4}{7} \times 420 = 240 and 37×420=180\frac{3}{7} \times 420 = 180.

Observed matches expected exactly. The chi-square value χ2=(OE)2E=0\chi^2 = \sum \frac{(O-E)^2}{E} = 0, so the null hypothesis holds.

The samples fit the 4:3 expectation perfectly. In NEET and CBSE problems on digestion and absorption, always convert ratios to fractions of the total before comparing — that’s the step most students skip.

Question 2 — Percentage Calculations

In a digestion and absorption experiment, 85 out of 340 units show a particular trait. What percentage does that represent, and what does it tell us?

85340×100=25%\frac{85}{340} \times 100 = 25\%.

A 25% frequency is exactly what we’d expect from a monohybrid cross recessive phenotype (14\frac{1}{4}), which tells us the trait is likely controlled by a single recessive allele.

25% — and more importantly, the number points to single-gene recessive inheritance. NEET loves this kind of reverse-engineering from data.

Question 3 — Rate Problem

If a process in digestion and absorption proceeds at 2.52.5 units per minute and we need 7575 units, how long does it take? What if the rate drops to 60%60\% due to a limiting factor?

Time =752.5=30= \frac{75}{2.5} = 30 minutes.

New rate =2.5×0.60=1.5= 2.5 \times 0.60 = 1.5 units/min. Time =751.5=50= \frac{75}{1.5} = 50 minutes.

30 minutes normally, 50 minutes with the limiting factor. Remember: biological rates rarely stay constant — temperature, pH, and substrate concentration all shift them.

For any numerical in Digestion And Absorption, write down what’s given, what’s asked, and the formula — in that order — before touching a calculator. Half the errors come from jumping to computation.

Question 4 — Working Backwards

We observe a final value of 128128 after 33 doubling cycles. What was the starting value?

Final == Initial ×2n\times 2^n, so 128=x×23=8x128 = x \times 2^3 = 8x.

x=1288=16x = \frac{128}{8} = 16.

Starting value was 16. Exponential growth patterns in digestion and absorption almost always reduce to N=N0×2nN = N_0 \times 2^n — memorise it.

Common Setup Mistakes

Students mix up ratio and percentage — a 3:1 ratio is 75:25, not 30:10. Always check the denominators add to the total.

These four problems cover the main numerical patterns you’ll face in Digestion And Absorption: ratios, percentages, rates, and exponential models. PYQs from the last five years of NEET have all followed this structure, so the weightage on practising them is high.

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