Neural: Tricky Problems from JEE/NEET

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Question

A neuron has [K+]in=140[K^+]_{in} = 140 mM and [K+]out=5[K^+]_{out} = 5 mM. Using the Nernst equation at 37°C, find the K⁺ equilibrium potential. Why is the actual resting potential (70-70 mV) less negative than this?

Solution — Step by Step

EK=61zlog10[K+]out[K+]inE_K = \dfrac{61}{z}\log_{10}\dfrac{[K^+]_{out}}{[K^+]_{in}} mV at 37°C, with z=+1z = +1.

EK=61×log10(5/140)=61×log10(0.0357)E_K = 61 \times \log_{10}(5/140) = 61 \times \log_{10}(0.0357).

log10(0.0357)1.447\log_{10}(0.0357) \approx -1.447, so EK61×(1.447)88E_K \approx 61 \times (-1.447) \approx -88 mV.

The actual resting potential is 70-70 mV because the membrane has small but nonzero permeability to Na⁺. Sodium leaking in pulls the potential slightly positive of pure EKE_K. The full expression is the Goldman equation.

Final answer: EK88E_K \approx -88 mV. Resting potential is less negative because of Na⁺ leak permeability.

Why This Works

The Nernst equation assumes the membrane is permeable to only one ion. Real membranes leak multiple ions, so the resting potential is a weighted average of each ion’s equilibrium potential, weighted by its permeability.

Alternative Method

If the question gives you Na⁺ concentrations too, apply Goldman directly instead of Nernst.

Most neural-system numericals come down to unit hygiene and remembering what each gate does at each phase. Draw the action potential graph before reading the question — it saves time.

Common Mistake

Plugging in z=2z = 2 for K⁺ or forgetting the sign when [in]>[out][in] > [out]. K⁺ is monovalent (z=1z=1) and the log of a number less than 1 is negative.

Do not confuse passive channels (follow the gradient) with active pumps (fight the gradient). This single distinction clears half of all neural-system doubts.

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