CBSE Weightage:

CBSE Class 10 Science — Chemical Reactions and Equations

CBSE Class 10 Science — Chemical Reactions and Equations — chapter overview, key concepts, solved examples, and exam strategy.

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Chapter Overview & Weightage

Chemical Reactions and Equations is Chapter 1 in CBSE Class 10 Science (NCERT). It is the opening chapter of the chemistry section and establishes vocabulary and concepts used throughout Class 10 and Class 11 chemistry.

This chapter carries 12–15 marks in the CBSE Class 10 Science board exam. Balancing equations, types of reactions, and oxidation-reduction identification are consistently high-scoring topics. At least one 5-mark question from this chapter appears in every board exam.

What this chapter covers:

  • Chemical equations and their characteristics
  • Balancing chemical equations
  • Types of chemical reactions (combination, decomposition, displacement, double displacement, redox)
  • Oxidation and reduction
  • Effects of oxidation in daily life (corrosion, rancidity)

Key Concepts You Must Know

What Makes a Chemical Reaction?

A chemical reaction occurs when:

  • A new substance with new properties is formed
  • The process is generally irreversible

Signs of a chemical reaction:

  1. Change in colour
  2. Evolution of gas (effervescence)
  3. Formation of precipitate
  4. Change in temperature
  5. Change in smell

Writing Chemical Equations

A word equation names substances in words. A symbol equation uses chemical formulas.

Skeletal equation (unbalanced): Mg+O2MgOMg + O_2 \rightarrow MgO

Balanced equation: 2Mg+O22MgO2Mg + O_2 \rightarrow 2MgO

Why balance? The Law of Conservation of Mass states matter is neither created nor destroyed. Atoms on both sides must be equal.

Types of Reactions

1. Combination (Synthesis): Two or more substances combine to form one new substance.

A+BABA + B \rightarrow AB

Example: CaO+H2OCa(OH)2CaO + H_2O \rightarrow Ca(OH)_2 (quicklime + water → slaked lime, releases heat)

2. Decomposition: One substance breaks down into two or more simpler substances.

ABA+BAB \rightarrow A + B

Types: thermal (heat), electrolytic (electricity), photolytic (light) Example: 2Pb3O4Δ6PbO+O22Pb_3O_4 \xrightarrow{\Delta} 6PbO + O_2

3. Displacement: A more reactive element displaces a less reactive element from its compound.

A+BCAC+BA + BC \rightarrow AC + B

Example: Zn+CuSO4ZnSO4+CuZn + CuSO_4 \rightarrow ZnSO_4 + Cu (Zinc is more reactive than copper)

4. Double Displacement: Exchange of ions between two compounds, often forming a precipitate.

AB+CDAD+CBAB + CD \rightarrow AD + CB

Example: Na2SO4+BaCl2BaSO4+2NaClNa_2SO_4 + BaCl_2 \rightarrow BaSO_4\downarrow + 2NaCl

5. Oxidation-Reduction (Redox): Oxidation and reduction always occur simultaneously.

  • Oxidation: gain of oxygen / loss of hydrogen / loss of electrons
  • Reduction: loss of oxygen / gain of hydrogen / gain of electrons

Important Formulas

  1. Write the skeletal equation
  2. Count atoms of each element on both sides
  3. Add coefficients (whole numbers) to balance — start with the most complex molecule
  4. Never change subscripts — only coefficients
  5. Balance H and O last

If a substance:

  • Gains O or Loses H → it is OXIDISED
  • Loses O or Gains H → it is REDUCED

The substance that gets oxidised is the reducing agent. The substance that gets reduced is the oxidising agent.


Solved Previous Year Questions

PYQ 1 — Balancing Equations

Q: Balance the following chemical equation: (CBSE Board 2023)

Fe+H2OFe3O4+H2Fe + H_2O \rightarrow Fe_3O_4 + H_2

Solution:

Step 1 — Unbalanced: Fe+H2OFe3O4+H2Fe + H_2O \rightarrow Fe_3O_4 + H_2

Step 2 — Balance Fe: 3 on right, put coefficient 3 on left: 3Fe+H2OFe3O4+H23Fe + H_2O \rightarrow Fe_3O_4 + H_2

Step 3 — Balance O: 4 on right (in Fe3O4Fe_3O_4), need 4 H2OH_2O on left: 3Fe+4H2OFe3O4+H23Fe + 4H_2O \rightarrow Fe_3O_4 + H_2

Step 4 — Balance H: 8 H on left (4 × H2OH_2O), need 4 H2H_2 on right:

3Fe+4H2OFe3O4+4H2\boxed{3Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2}

Verify: Fe: 3=3 ✓, H: 8=8 ✓, O: 4=4 ✓


PYQ 2 — Types of Reactions

Q: Identify the type of reaction and the oxidising and reducing agents in: (CBSE 2022)

CuO+H2Cu+H2OCuO + H_2 \rightarrow Cu + H_2O

Solution:

Type: This is a redox reaction (displacement type within redox context).

Oxidation-Reduction analysis:

  • H2H2OH_2 \rightarrow H_2O: H₂ gains oxygen → H₂ is oxidised → H₂ is the reducing agent
  • CuOCuCuO \rightarrow Cu: CuO loses oxygen → CuO is reduced → CuO is the oxidising agent

PYQ 3 — Corrosion and Rancidity

Q: What is rancidity? State two methods to prevent it. (CBSE Board — 2 marks)

Solution:

Rancidity is the deterioration of fats and oils due to oxidation, producing unpleasant smell and taste.

Prevention methods:

  1. Antioxidants — substances like BHA (Butylated Hydroxyanisole) added to packaged food that get preferentially oxidised, protecting the fats
  2. Inert gas packaging — chips and snacks are packed in nitrogen gas, which displaces oxygen and prevents oxidation
  3. (Also acceptable): Refrigeration (slows oxidation), opaque packaging (prevents light-induced oxidation)

Difficulty Distribution

DifficultyTopicMarks
Easy (25%)Identify type of reaction; word to symbol equation1–2 marks
Medium (45%)Balance equations; identify oxidising/reducing agents; state effects2–3 marks
Hard (30%)Write balanced equation for described reaction; combined analysis4–5 marks

Expert Strategy

In board exams, equations with fractions (like 12O2\frac{1}{2}O_2) are not acceptable — always multiply through to clear fractions. For example: H2+12O2H2OH_2 + \frac{1}{2}O_2 \rightarrow H_2O must be written as 2H2+O22H2O2H_2 + O_2 \rightarrow 2H_2O.

Memorise these key balanced equations — they appear directly in board exams:

  • 2Mg+O22MgO2Mg + O_2 \rightarrow 2MgO (Magnesium burning)
  • Zn+H2SO4ZnSO4+H2Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2\uparrow (Zinc + dilute acid)
  • 2HCl+Na2CO32NaCl+H2O+CO22HCl + Na_2CO_3 \rightarrow 2NaCl + H_2O + CO_2\uparrow (Acid + carbonate)
  • 3Fe+4H2OFe3O4+4H23Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2 (Rust formation at high temperature)

Common Traps

Trap 1 — Changing subscripts instead of coefficients: If you have H2H_2 on one side and H4H_4 on another, you CANNOT write H4H_4 as a product — there’s no such stable molecule. Only add coefficients in front of the formula, never change the formula itself.

Trap 2 — Confusing oxidising and reducing agents: The reducing agent is oxidised (it causes reduction by giving electrons/getting itself oxidised). Students flip this. Remember: Reducing agent gets oxidised (loses electrons). Oxidising agent gets reduced (gains electrons).

Trap 3 — Not writing state symbols: CBSE board answers should include state symbols: (s) solid, (l) liquid, (g) gas, (aq) aqueous. Missing state symbols lose marks in some questions.

Trap 4 — Confusing decomposition with displacement: In decomposition, one substance breaks into simpler parts. In displacement, one element pushes another out of its compound. A reaction like 2KClO32KCl+3O22KClO_3 \rightarrow 2KCl + 3O_2 is decomposition (one compound splits). A reaction like Fe+CuSO4FeSO4+CuFe + CuSO_4 \rightarrow FeSO_4 + Cu is displacement (Fe replaces Cu).