Friedel-Crafts alkylation and acylation — mechanism with AlCl₃ catalyst

medium JEE-MAIN JEE-ADVANCED JEE Main 2023 3 min read

Question

Explain the Friedel-Crafts alkylation and acylation of benzene with mechanisms. Why is acylation preferred over alkylation for preparing monosubstituted products?

(JEE Main 2023, similar pattern)


Solution — Step by Step

Benzene reacts with an alkyl halide in the presence of anhydrous AlCl3_3 (Lewis acid catalyst) to form an alkylbenzene:

C6H6+RClAlCl3C6H5R+HCl\text{C}_6\text{H}_6 + \text{RCl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{R} + \text{HCl}

Mechanism (electrophilic aromatic substitution):

  1. AlCl3_3 + RCl → R+^+ + AlCl4_4^- (generation of electrophile — carbocation)
  2. R+^+ attacks the π\pi-electron cloud of benzene → arenium ion (sigma complex)
  3. Loss of H+^+ from the sigma complex restores aromaticity → product + HCl
  4. AlCl4_4^- + H+^+ → AlCl3_3 + HCl (catalyst regenerated)

Benzene reacts with an acyl halide (RCOCl) in the presence of AlCl3_3 to form an aryl ketone:

C6H6+RCOClAlCl3C6H5COR+HCl\text{C}_6\text{H}_6 + \text{RCOCl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{COR} + \text{HCl}

Mechanism:

  1. AlCl3_3 + RCOCl → RCO+^+ + AlCl4_4^- (acylium ion — the electrophile)
  2. RCO+^+ attacks benzene → arenium ion
  3. Loss of H+^+ → aryl ketone + HCl

The acylium ion (RCO+^+) is stabilised by resonance (R-C+=OR-C=O+\text{R-C}^+=\text{O} \leftrightarrow \text{R-C}=\text{O}^+), so unlike alkylation, there is no carbocation rearrangement.

Problem with alkylation: The alkyl group is an electron-donating group (activating). So the product (alkylbenzene) is MORE reactive than benzene, leading to polyalkylation — getting a clean monosubstituted product is difficult.

Advantage of acylation: The acyl group (C=O) is an electron-withdrawing group (deactivating). So the product (aryl ketone) is LESS reactive than benzene. The reaction naturally stops at mono-substitution.

To get a monoalkylbenzene cleanly: first acylate, then reduce the C=O to CH2_2 using Clemmensen reduction (Zn-Hg/HCl) or Wolff-Kishner reduction (NH2_2NH2_2/KOH).


Why This Works

Both reactions are examples of electrophilic aromatic substitution — the fundamental reaction pattern of benzene. AlCl3_3 (a Lewis acid with an incomplete octet) acts as a catalyst by generating a strong electrophile from a mild one. The aromatic ring’s π\pi-electrons attack the electrophile, and the subsequent loss of H+^+ preserves aromaticity.

The acylation-then-reduction strategy (sometimes called the Friedel-Crafts acylation route) is one of the most important synthetic sequences in organic chemistry for JEE.


Alternative Method — Using Acid Anhydrides

Acid anhydrides can replace acyl halides in Friedel-Crafts acylation:

C6H6+(RCO)2OAlCl3C6H5COR+RCOOH\text{C}_6\text{H}_6 + (\text{RCO})_2\text{O} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{COR} + \text{RCOOH}

Friedel-Crafts reaction does NOT work with: (1) deactivated rings (nitrobenzene, benzoic acid), (2) vinyl or aryl halides, (3) NH2_2-substituted rings (the amine coordinates with AlCl3_3, deactivating the catalyst). These limitations are heavily tested in JEE.


Common Mistake

In alkylation, the intermediate carbocation can rearrange via hydride or methyl shifts. For example, using n-propyl chloride with AlCl3_3 gives mainly isopropylbenzene (cumene), not n-propylbenzene, because the primary carbocation rearranges to the more stable secondary carbocation. Students who ignore rearrangement predict the wrong product.

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