Question
5.6 L of a gas at STP has a mass of 11 g. Find the molecular mass of the gas.
Solution — Step by Step
At STP (Standard Temperature and Pressure: 0°C and 1 atm), one mole of any ideal gas occupies 22.4 L.
This is a fundamental result from the ideal gas law. It is the same for ALL gases regardless of molecular mass — only the number of molecules (moles) matters.
Key fact: 22.4 L at STP = 1 mole of gas.
So 5.6 L of gas at STP = 0.25 moles.
Molecular mass = 44 g/mol.
This matches: (), (44), or (44).
Without additional information, we conclude the molecular mass is 44 g/mol.
Why This Works
The molar volume at STP (22.4 L/mol) comes from the ideal gas law at K and atm:
This is independent of the identity of the gas — all ideal gases have the same volume per mole at the same conditions. This is essentially Avogadro’s hypothesis: equal volumes of gases at the same T and P contain equal numbers of molecules.
The molecular mass is then simply mass per mole — total mass divided by number of moles.
Alternative Method — Direct Proportion
At STP: 22.4 L has mass = 1 molecular mass (M) grams.
So 5.6 L has mass = grams.
Given mass = 11 g: g/mol.
Same answer, one-step proportion.
Common Mistake
Using 22.4 L for conditions other than STP. The molar volume 22.4 L/mol applies specifically at STP (0°C, 1 atm). At different temperatures or pressures, the molar volume changes. Some problems specify “at 27°C and 1 atm” — then use L/mol. Always check whether the problem says STP before using 22.4.