Find the area of trapezium with parallel sides 8cm and 12cm and height 5cm

medium CBSE JEE-MAIN 3 min read

Question

Find the area of a trapezium with parallel sides of length 8 cm and 12 cm, and a height (perpendicular distance between the parallel sides) of 5 cm.

Solution — Step by Step

A trapezium (called a trapezoid in American English) is a quadrilateral with exactly one pair of parallel sides.

The formula for the area of a trapezium is:

Area=12×(a+b)×h\text{Area} = \frac{1}{2} \times (a + b) \times h

where aa and bb are the lengths of the two parallel sides (called the “bases”), and hh is the perpendicular height between them.

From the problem:

  • First parallel side: a=8a = 8 cm
  • Second parallel side: b=12b = 12 cm
  • Height: h=5h = 5 cm
Area=12×(8+12)×5\text{Area} = \frac{1}{2} \times (8 + 12) \times 5 =12×20×5= \frac{1}{2} \times 20 \times 5 =12×100= \frac{1}{2} \times 100 =50 cm2= \boxed{50 \text{ cm}^2}

Why This Works

A trapezium can be cut into a rectangle and two triangles. The average of the two parallel sides gives the width of an equivalent rectangle, and multiplying by the height gives the area:

Area=a+b2average base×h\text{Area} = \underbrace{\frac{a + b}{2}}_{\text{average base}} \times h

Here, the average base = (8+12)/2=10(8+12)/2 = 10 cm. Multiplying by height 55 cm gives 5050 cm².

This formula also works for parallelograms (where a=ba = b, giving Area=a×h\text{Area} = a \times h) and triangles (where b=0b = 0, giving Area=12ah\text{Area} = \frac{1}{2} ah). The trapezium formula is the general form.

Alternative Method

You can split the trapezium into simpler shapes:

Option 1: Draw a diagonal to split into two triangles:

  • Triangle 1: base = 8 cm, height = 5 cm → Area = 12×8×5=20\frac{1}{2} \times 8 \times 5 = 20 cm²
  • Triangle 2: base = 12 cm, height = 5 cm → Area = 12×12×5=30\frac{1}{2} \times 12 \times 5 = 30 cm²
  • Total = 50 cm² ✓

Option 2: Draw a perpendicular from one end of the shorter side to the longer side, splitting into a rectangle (8 × 5) and a triangle. This works only for a right trapezium.

Common Mistake

Students sometimes use the formula Area=base×height\text{Area} = \text{base} \times \text{height} (for a rectangle or parallelogram) and multiply one parallel side by the height: 8×5=408 \times 5 = 40 or 12×5=6012 \times 5 = 60. Both are wrong. For a trapezium, you must use the average of the two parallel sides: (8+12)/2=10(8+12)/2 = 10. The formula 12(a+b)h\frac{1}{2}(a+b)h accounts for the fact that the trapezium is neither as wide as its longer side nor as narrow as its shorter side throughout its height.

Units matter: since the answer is an area, the unit is cm² (not just cm). In CBSE exams, writing 50 cm instead of 50 cm² costs you a mark. Always write the unit explicitly for areas and volumes.

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