Direct and Inverse Proportion — Speed and Time Example

medium CBSE CBSE Class 8 4 min read

Question

A car travelling at 60 km/h covers a distance in 4 hours. How long will it take if the speed is increased to 80 km/h?

Also: 12 workers can build a wall in 10 days. How many days will 15 workers take?

Two problems, one concept — we’ll see exactly why they behave differently.


Solution — Step by Step

First, ask yourself: as one quantity increases, does the other increase or decrease?

  • Speed ↑, Time ↓ → they move in opposite directions → Inverse proportion
  • Workers ↑, Days ↓ → same pattern → also Inverse proportion

This single check saves you from setting up the ratio upside-down.

In inverse proportion, the product stays constant. So:

Speed1×Time1=Speed2×Time2\text{Speed}_1 \times \text{Time}_1 = \text{Speed}_2 \times \text{Time}_2

This works because distance is fixed. More speed means the same distance is covered in less time.

Substituting:

60×4=80×t260 \times 4 = 80 \times t_2 240=80×t2240 = 80 \times t_2 t2=24080=3 hourst_2 = \frac{240}{80} = 3 \text{ hours}

Answer: The car takes 3 hours at 80 km/h.

More workers → fewer days, so again inverse proportion:

Workers1×Days1=Workers2×Days2\text{Workers}_1 \times \text{Days}_1 = \text{Workers}_2 \times \text{Days}_2 12×10=15×d212 \times 10 = 15 \times d_2 120=15×d2120 = 15 \times d_2 d2=12015=8 daysd_2 = \frac{120}{15} = 8 \text{ days}

Answer: 15 workers will finish the wall in 8 days.


Why This Works

The underlying idea is that the total work or total distance stays constant. In Part 1, distance = speed × time. When speed goes up, time must come down by the same factor — otherwise the product (distance) would change.

In Part 2, think of “total work” as worker-days. 12 workers × 10 days = 120 worker-days of effort. If you hire 15 workers, you still need 120 worker-days of total effort, so each worker works fewer days.

This is why the product rule — x1×y1=x2×y2x_1 \times y_1 = x_2 \times y_2 — is the go-to tool for inverse proportion. Write it down first, fill in three values, solve for the fourth.

x1×y1=x2×y2x_1 \times y_1 = x_2 \times y_2

Use when: more of one quantity means less of the other.


Alternative Method — Unitary Method

Some students prefer this approach, and it’s great for checking your answer.

Part 1 (Speed and Time):

At 60 km/h → time = 4 hours At 1 km/h → time = 4 × 60 = 240 hours (to cover the same distance at walking pace!) At 80 km/h → time = 240 ÷ 80 = 3 hours

Part 2 (Workers and Days):

12 workers → 10 days 1 worker → 10 × 12 = 120 days (one person doing everything alone) 15 workers → 120 ÷ 15 = 8 days

The logic: first bring one quantity to 1, then scale back up. It’s slower than the product rule but makes the reasoning very visible.


Common Mistake

The most common error is treating all proportion problems as direct proportion and writing:

x1y1=x2y2\frac{x_1}{y_1} = \frac{x_2}{y_2}

For the speed problem, this gives 604=80t2\frac{60}{4} = \frac{80}{t_2}, which gives t2=5.33t_2 = 5.33 hours — meaning a faster car takes longer. That’s physically absurd, but many students don’t pause to check.

Always ask: “If this quantity goes up, does the other go up or down?” If down → invert one ratio (or use the product rule).

Quick check after solving: Does your answer make physical sense?

Faster speed → should give fewer hours. More workers → should give fewer days. If your answer goes the wrong way, you’ve used the wrong proportion type.

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