Length of Arc and Area of Sector — Circle Formulas

easy CBSE NCERT Class 10 3 min read

Question

A circle has radius 7 cm. A sector is cut from it with a central angle of 60°. Find:

  1. The length of the arc
  2. The area of the sector

(Use π = 22/7)


Solution — Step by Step

Before we use any formula, we need the angle in radians — not degrees. The conversion is:

θ=π180×60°=π3 radians\theta = \frac{\pi}{180} \times 60° = \frac{\pi}{3} \text{ radians}

This matters because the arc length and sector area formulas only work directly with radians.

Arc length uses the formula L=rθL = r\theta, where rr is the radius and θ\theta is in radians.

L=7×π3=7π3=7×22/73=2237.33 cmL = 7 \times \frac{\pi}{3} = \frac{7\pi}{3} = \frac{7 \times 22/7}{3} = \frac{22}{3} \approx 7.33 \text{ cm}

Arc length = 22/3 cm ≈ 7.33 cm

Sector area uses A=12r2θA = \frac{1}{2}r^2\theta. Plug in r=7r = 7 and θ=π/3\theta = \pi/3:

A=12×72×π3=12×49×22/73=12×49×2221=12×107821A = \frac{1}{2} \times 7^2 \times \frac{\pi}{3} = \frac{1}{2} \times 49 \times \frac{22/7}{3} = \frac{1}{2} \times \frac{49 \times 22}{21} = \frac{1}{2} \times \frac{1078}{21} A=12×1543=77325.67 cm2A = \frac{1}{2} \times \frac{154}{3} = \frac{77}{3} \approx 25.67 \text{ cm}^2

Sector area = 77/3 cm² ≈ 25.67 cm²


Why This Works

Think of a full circle as a sector with θ=2π\theta = 2\pi radians. The full circumference is 2πr2\pi r, and arc length L=rθL = r\theta gives exactly that when θ=2π\theta = 2\pi. So the formula is just “what fraction of the full circle is this sector?” scaled to the circumference.

Same logic for area: full circle area is πr2\pi r^2. Our formula 12r2θ\frac{1}{2}r^2\theta at θ=2π\theta = 2\pi gives 12r22π=πr2\frac{1}{2}r^2 \cdot 2\pi = \pi r^2. Everything checks out.

The radian conversion isn’t magic — it’s just the natural unit for measuring rotation. When we write 60°=π/360° = \pi/3, we’re saying “this angle is 1/61/6 of a half-turn,” which is exactly the fraction of the circle we’re cutting.


Alternative Method

CBSE Class 10 NCERT also teaches the degree-based versions of these formulas directly:

Arc Length=θ360°×2πr\text{Arc Length} = \frac{\theta}{360°} \times 2\pi r Sector Area=θ360°×πr2\text{Sector Area} = \frac{\theta}{360°} \times \pi r^2

For our problem:

L=60360×2×227×7=16×44=223 cmL = \frac{60}{360} \times 2 \times \frac{22}{7} \times 7 = \frac{1}{6} \times 44 = \frac{22}{3} \text{ cm} A=60360×227×49=16×154=773 cm2A = \frac{60}{360} \times \frac{22}{7} \times 49 = \frac{1}{6} \times 154 = \frac{77}{3} \text{ cm}^2

Same answers, different route. For board exams, this degree-based form is perfectly acceptable and avoids the radian conversion step.

The degree-based formulas are safer for CBSE Class 10 since the NCERT introduces them first. Save the radian forms for Class 11 and JEE prep — they’re the same thing, just written differently.


Common Mistake

Forgetting to convert degrees to radians before using L=rθL = r\theta.

Students plug in θ=60\theta = 60 directly and get L=7×60=420L = 7 \times 60 = 420 cm — which is absurd (longer than the radius by 60 times!). The formula L=rθL = r\theta demands θ\theta in radians. If your angle is in degrees, either convert first or use the degree-based formula θ360×2πr\frac{\theta}{360} \times 2\pi r. Both routes give the same answer; picking one and sticking with it prevents this error entirely.

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