Multiply (x + 3)(x + 2) Using FOIL

easy CBSE CBSE Class 8 3 min read

Question

Multiply (x + 3)(x + 2) using the FOIL method.

Solution — Step by Step

FOIL is just a memory tool for multiplying two binomials — First, Outer, Inner, Last. Each letter tells you which pair of terms to multiply. We’ll multiply all four pairs and then combine.

The First terms are x (from the first bracket) and x (from the second bracket).

x×x=x2x \times x = x^2

Outer means the terms on the far outside — x and +2.

x×2=2xx \times 2 = 2x

Inner means the terms closest to each other in the middle — +3 and x.

3×x=3x3 \times x = 3x

Last terms are +3 and +2.

3×2=63 \times 2 = 6

Now collect all four results: x2+2x+3x+6x^2 + 2x + 3x + 6. Combine the like terms 2x and 3x:

x2+5x+6\boxed{x^2 + 5x + 6}

Why This Works

When we multiply (x + 3)(x + 2), we’re really asking: “what is each term in the first bracket × each term in the second bracket?” The distributive property says (x + 3)(x + 2) = x(x + 2) + 3(x + 2). FOIL is just this distribution done in a neat, memorable order.

The 5x in the middle comes from adding the outer and inner products — 2x + 3x. This middle term is where students most often make errors, so it’s worth pausing here.

For any two binomials (x + a)(x + b), the middle term is always (a + b)x and the last term is always ab. So for (x + 3)(x + 2), the answer is x² + (3+2)x + (3×2) = x² + 5x + 6. Once you see this pattern, you can skip FOIL for simple cases and write the answer directly.

Alternative Method

We can use the standard distributive method (also called the “each-by-each” method), which is what FOIL actually is under the hood.

Treat (x + 2) as a single block and distribute (x + 3) over it:

x(x+2)+3(x+2)x(x + 2) + 3(x + 2) =x2+2x+3x+6= x^2 + 2x + 3x + 6 =x2+5x+6= x^2 + 5x + 6

Same answer, same steps — just written differently. This form is more useful when you move to multiplying a trinomial by a binomial later in Class 9-10.

Common Mistake

The most common error is forgetting the Outer and Inner steps — students multiply only First and Last, writing x² + 6 and missing the 5x entirely. This happens because and 6 feel like “the obvious parts.” Always ask: where is the middle term coming from? If your answer has no x term when multiplying two linear expressions, something went wrong.

Another frequent slip: writing x² + 2x + 3x + 6 correctly but then adding the like terms as x² + 5x² + 6, treating 5x as 5x². Keep track of the exponent — 2x + 3x = 5x, not 5x².

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