Question
Classify by degree and number of terms. What factoring strategy works for each polynomial type?
(CBSE 9 & 10 — polynomials chapter)
Solution — Step by Step
| Degree | Name | Example |
|---|---|---|
| 0 | Constant | |
| 1 | Linear | |
| 2 | Quadratic | |
| 3 | Cubic | |
| 4 | Quartic (Biquadratic) |
Our polynomial has degree 4 (highest power of ), so it’s a quartic/biquadratic polynomial.
| Terms | Name |
|---|---|
| 1 | Monomial (e.g., ) |
| 2 | Binomial (e.g., ) |
| 3 | Trinomial (e.g., ) |
has 3 terms → trinomial.
| Type | Strategy |
|---|---|
| Common factor | Take out GCF first (always check this!) |
| Quadratic trinomial | Split middle term or use formula |
| Difference of squares | |
| Perfect square | |
| Sum/difference of cubes | |
| Biquadratic | Substitute , reduce to quadratic |
Why This Works
graph TD
A["Factor a polynomial"] --> B{"Common factor?"}
B -->|"Yes"| C["Factor out GCF first"]
B -->|"No"| D{"Degree?"}
C --> D
D -->|"2 (quadratic)"| E{"Type?"}
D -->|"3 (cubic)"| F["Try factor theorem<br/>or grouping"]
D -->|"4 (biquadratic)"| G["Substitute t = x²<br/>Solve as quadratic in t"]
E -->|"a² - b²"| H["(a+b)(a-b)"]
E -->|"Trinomial"| I["Split middle term<br/>or quadratic formula"]
E -->|"Perfect square"| J["(a ± b)²"]
Classification guides strategy. A quadratic trinomial calls for middle-term splitting. A biquadratic with only even powers calls for substitution. Knowing the type saves time by pointing you to the right technique immediately.
Alternative Method — Factor Theorem
For any polynomial : if , then is a factor. Try small integer values () to find roots. This works for all degrees but is most practical for cubics and quartics.
For CBSE 10: the factor theorem combined with synthetic division is the fastest way to factor cubics. Find one root by trial, divide out the linear factor, and you’re left with a quadratic that you can factor normally.
Common Mistake
Students try to factor by splitting the middle term as if it were a quadratic in . But it’s a quadratic in — substitute first to get , then check if this quadratic factors. Here the discriminant is , so it doesn’t factor over the reals. Not every polynomial can be factored — recognising this saves time.