NEET Weightage: 3-4%

NEET Chemistry — Chemical Kinetics Complete Chapter Guide

Chemical Kinetics for NEET.

5 min read

Chapter Overview & Weightage

Chemical Kinetics is about HOW FAST reactions happen. While thermodynamics tells us whether a reaction is possible, kinetics tells us whether it will actually occur at a meaningful rate. NEET loves first-order kinetics and the Arrhenius equation.

Chemical Kinetics carries 3-4% weightage in NEET with 1-2 questions. First-order rate law and Arrhenius equation are tested most frequently.

YearNEET Q CountKey Topics Tested
20252Half-life, Arrhenius equation
20241First-order integrated rate law
20232Order determination, activation energy
20222Rate law, half-life
20211Arrhenius, temperature dependence
graph TD
    A[Chemical Kinetics] --> B[Rate of Reaction]
    A --> C[Rate Law]
    A --> D[Integrated Rate Laws]
    A --> E[Temperature Dependence]
    C --> F[Order of Reaction]
    C --> G[Rate Constant k]
    D --> H[Zero Order]
    D --> I[First Order]
    D --> J[Second Order]
    E --> K[Arrhenius Equation]
    E --> L[Activation Energy]
    E --> M[Collision Theory]

Key Concepts You Must Know

Tier 1 (Always asked)

  • Rate law: r=k[A]m[B]nr = k[A]^m[B]^n (order = m+nm + n)
  • First-order: k=2.303tlog[A]0[A]tk = \dfrac{2.303}{t}\log\dfrac{[A]_0}{[A]_t}, t1/2=0.693/kt_{1/2} = 0.693/k
  • Arrhenius equation: k=AeEa/RTk = Ae^{-E_a/RT}
  • Half-life of first-order is independent of initial concentration

Tier 2 (Frequently asked)

  • Zero order: [A]=[A]0kt[A] = [A]_0 - kt, t1/2=[A]0/(2k)t_{1/2} = [A]_0/(2k)
  • Determining order from experimental data
  • Units of rate constant for different orders
  • Effect of temperature: rate roughly doubles for every 10 K rise

Tier 3 (Occasional)

  • Collision theory and steric factor
  • Pseudo first-order reactions
  • Molecularity vs order distinction

Important Formulas

OrderRate LawIntegrated FormHalf-lifeUnits of k
0r=kr = k[A]=[A]0kt[A] = [A]_0 - kt[A]0/(2k)[A]_0/(2k)mol L1^{-1} s1^{-1}
1r=k[A]r = k[A]ln[A]=ln[A]0kt\ln[A] = \ln[A]_0 - kt0.693/k0.693/ks1^{-1}
2r=k[A]2r = k[A]^21/[A]=1/[A]0+kt1/[A] = 1/[A]_0 + kt1/(k[A]0)1/(k[A]_0)L mol1^{-1} s1^{-1}
k=AeEa/RTk = Ae^{-E_a/RT}

Log form: logk=logAEa2.303RT\log k = \log A - \dfrac{E_a}{2.303RT}

Two-temperature form:

logk2k1=Ea2.303R(1T11T2)\log\frac{k_2}{k_1} = \frac{E_a}{2.303R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)

For first-order reactions, the fraction remaining after nn half-lives is (1/2)n(1/2)^n. After 3 half-lives, only 12.5% remains. After 10 half-lives, less than 0.1% remains. This shortcut eliminates the need for log calculations in many NEET problems.


Solved Previous Year Questions

PYQ 1 — NEET 2024

Problem: A first-order reaction has a rate constant of 0.06930.0693 min1^{-1}. How long will it take for 75% of the reactant to decompose?

Solution:

75% decomposed means 25% remains, so [A]/[A]0=0.25=1/4=(1/2)2[A]/[A]_0 = 0.25 = 1/4 = (1/2)^2.

This means 2 half-lives have passed.

t1/2=0.6930.0693=10 mint_{1/2} = \frac{0.693}{0.0693} = 10 \text{ min} t=2×10=20 mint = 2 \times 10 = \mathbf{20 \text{ min}}

PYQ 2 — NEET 2023

Problem: If the activation energy of a reaction is 50 kJ/mol, by what factor does the rate increase when temperature is raised from 300 K to 310 K? (R=8.314R = 8.314 J/mol/K)

Solution:

logk2k1=Ea2.303R(1T11T2)\log\frac{k_2}{k_1} = \frac{E_a}{2.303R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right) =500002.303×8.314(13001310)= \frac{50000}{2.303 \times 8.314}\left(\frac{1}{300} - \frac{1}{310}\right) =5000019.147(1093000)=2612×1.075×104=0.281= \frac{50000}{19.147}\left(\frac{10}{93000}\right) = 2612 \times 1.075 \times 10^{-4} = 0.281 k2k1=100.2811.91\frac{k_2}{k_1} = 10^{0.281} \approx \mathbf{1.91}

Rate approximately doubles — consistent with the general rule.


Difficulty Distribution

Difficulty% of QuestionsWhat to Expect
Easy40%Half-life, order from units
Medium45%Arrhenius two-temperature, integrated rate law
Hard15%Order determination from data, pseudo reactions

Expert Strategy

Week 1: First-order kinetics is the most tested. Master the integrated rate law, half-life, and the “fraction remaining” shortcut.

Week 2: Arrhenius equation — both the log form and the two-temperature form. Most NEET problems give you two temperatures and two rate constants and ask for EaE_a.

Week 3: Distinguishing order from experimental data. If t1/2t_{1/2} is constant, it is first order. If t1/2t_{1/2} changes with concentration, check zero or second order.


Common Traps

Trap 1 — Molecularity and order are different. Molecularity is a theoretical concept (number of molecules in the rate-determining step) and is always a whole number. Order is experimental and can be fractional. A reaction can be bimolecular but first order overall.

Trap 2 — Half-life of zero-order depends on concentration. t1/2=[A]0/(2k)t_{1/2} = [A]_0/(2k). Unlike first order, if you double the initial concentration, the half-life doubles. Students assume all half-lives are constant — only first-order has this property.

Trap 3 — Units of EaE_a in Arrhenius. Use J/mol when R=8.314R = 8.314 J/mol/K. If EaE_a is given in kJ/mol, convert to J/mol first. This is the same unit trap as in thermodynamics.