Electromagnetic induction applications — generator, transformer, eddy currents

medium CBSE JEE-MAIN NEET 3 min read
Tags Emi

Question

How do generators, transformers, and eddy current devices work based on electromagnetic induction? What is the underlying principle for each?

Solution — Step by Step

A coil of NN turns and area AA rotates with angular velocity ω\omega in a uniform magnetic field BB. The magnetic flux through the coil changes continuously:

Φ=NBAcos(ωt)\Phi = NBA\cos(\omega t)

By Faraday’s law, the induced EMF is:

ε=dΦdt=NBAωsin(ωt)\varepsilon = -\frac{d\Phi}{dt} = NBA\omega\sin(\omega t)

The peak EMF is ε0=NBAω\varepsilon_0 = NBA\omega. The output is sinusoidal (AC). Slip rings and brushes transfer the current to the external circuit.

A transformer transfers electrical energy between two coils wound on the same iron core using mutual induction.

The AC in the primary coil creates a changing magnetic flux in the core, which induces an EMF in the secondary coil.

VsVp=NsNp=IpIs\frac{V_s}{V_p} = \frac{N_s}{N_p} = \frac{I_p}{I_s}
  • Step-up: Ns>NpN_s > N_p (increases voltage, decreases current)
  • Step-down: N_s < N_p (decreases voltage, increases current)

For an ideal transformer: VpIp=VsIsV_p I_p = V_s I_s (power is conserved).

When a conductor moves through a magnetic field (or when the field through it changes), loops of current (eddy currents) are induced within the conductor itself.

Harmful effects: Energy loss as heat in transformer cores, motors Remedy: Laminated cores (thin insulated sheets reduce eddy current loops)

Useful applications:

  • Electromagnetic braking (no friction wear)
  • Induction furnace (heat generation)
  • Speedometers
  • Metal detectors
graph TD
    A[Faraday's Law] --> B[Changing flux induces EMF]
    B --> C[AC Generator]
    B --> D[Transformer]
    B --> E[Eddy Currents]
    C --> F["Rotating coil: EMF = NBAw sin wt"]
    D --> G["Mutual induction: Vs/Vp = Ns/Np"]
    E --> H["Bulk conductor currents"]
    H --> I[Harmful: core losses]
    H --> J[Useful: braking, heating]

Why This Works

All three applications are governed by Faraday’s law of electromagnetic induction:

ε=dΦBdt\varepsilon = -\frac{d\Phi_B}{dt}

The negative sign (Lenz’s law) ensures the induced current opposes the change that caused it — this is nature’s way of conserving energy.

DevicePrincipleEnergy Conversion
AC GeneratorEMI (changing flux by rotation)Mechanical \to Electrical
TransformerMutual inductionElectrical \to Electrical (voltage change)
Eddy current brakeEMI (conductor in changing field)Kinetic \to Heat
Induction furnaceEddy currentsElectrical \to Heat

Alternative Method

For JEE numericals on generators, remember:

  • Peak EMF: ε0=NBAω\varepsilon_0 = NBA\omega
  • RMS EMF: εrms=ε02\varepsilon_{rms} = \frac{\varepsilon_0}{\sqrt{2}}
  • Frequency: f=ω/2π=f = \omega / 2\pi = rotational frequency of the coil

For transformers: efficiency =VsIsVpIp×100%= \frac{V_s I_s}{V_p I_p} \times 100\%. Real transformers have 90-99% efficiency. Losses come from: copper loss (resistance heating), iron loss (eddy currents + hysteresis), and flux leakage.

Common Mistake

Students write the generator EMF as ε=NBAωcos(ωt)\varepsilon = NBA\omega\cos(\omega t), which gives zero EMF at t=0t = 0. Whether the expression uses sin or cos depends on the initial position of the coil. If the coil starts parallel to the field (flux = 0 at t=0t = 0), use cos\cos for flux and sin\sin for EMF. If the coil starts perpendicular to the field, use sin\sin for flux and cos\cos for EMF. Always check the initial condition given in the question.

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