Ohm's law experiment — plot V-I graph and find resistance

medium CBSE CBSE 2024 3 min read

Question

In an experiment to verify Ohm’s law, the following readings were obtained:

Voltage (V)1.02.03.04.05.0
Current (A)0.250.500.751.001.25

Plot the V-I graph. From the graph, determine the resistance of the resistor. Is the resistor ohmic?

(CBSE 2024, similar pattern)


Solution — Step by Step

Take voltage (V) on the x-axis and current (I) on the y-axis. Choose a suitable scale — for example, 1 cm = 1 V on x-axis and 1 cm = 0.25 A on y-axis.

Plot the five data points: (1.0, 0.25), (2.0, 0.50), (3.0, 0.75), (4.0, 1.00), (5.0, 1.25).

All five points lie on a straight line passing through the origin. This confirms a linear relationship between V and I — exactly what Ohm’s law predicts.

Ohm’s law states V=IRV = IR, which means R=V/IR = V/I.

Pick any point on the line. Using (4.0, 1.00):

R=VI=4.01.00=4ΩR = \frac{V}{I} = \frac{4.0}{1.00} = \mathbf{4 \, \Omega}

We can verify with another point: R=2.0/0.50=4ΩR = 2.0 / 0.50 = 4 \, \Omega. Same answer — consistent.

Yes. Since the V-I graph is a straight line through the origin, the resistance is constant at all voltages. A device that follows this linear relationship is called an ohmic conductor.

Non-ohmic devices (like diodes or filament bulbs) would give a curved V-I graph.


Why This Works

Ohm’s law (V=IRV = IR) says that for a conductor at constant temperature, the current through it is directly proportional to the voltage across it. The proportionality constant is the resistance RR.

On a V-I graph, this proportionality shows up as a straight line through the origin. The slope of the graph (if I is on y-axis and V on x-axis) gives 1/R1/R, and the inverse of the slope gives RR. A steeper line means lower resistance (more current for the same voltage).

The “constant temperature” condition matters because resistance changes with temperature. That’s why a filament bulb (which heats up as current increases) doesn’t obey Ohm’s law — its V-I graph curves.


Alternative Method — Calculating slope directly

The slope of the I vs V graph is:

slope=ΔIΔV=1.250.255.01.0=1.004.0=0.25 A/V\text{slope} = \frac{\Delta I}{\Delta V} = \frac{1.25 - 0.25}{5.0 - 1.0} = \frac{1.00}{4.0} = 0.25 \text{ A/V}

Since slope =1/R= 1/R, we get R=1/0.25=4ΩR = 1/0.25 = 4 \, \Omega.

In the CBSE practical exam, always draw the graph on graph paper with a sharp pencil, mark the plotted points as small circles (not dots), and draw a smooth best-fit line. Write the scale clearly. The examiner checks all of this. Also, the resistance should be calculated from the graph line, not just from the table — that’s the whole point of the graphical method.


Common Mistake

Many students plot V on the y-axis and I on the x-axis (the reverse of what CBSE expects). While both are technically correct physics, the CBSE marking scheme typically expects V on x-axis and I on y-axis. Check your question paper — if it says “plot V-I characteristics,” V comes first (x-axis). Getting the axes wrong can cost you graph-related marks.

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